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Fixed user ID for JPA impl

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This commit is contained in:
Volodymyr Babak 2018-02-12 19:12:08 +02:00
parent 69422fea0e
commit ead30d700b
1 changed files with 7 additions and 4 deletions
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11
dao/src/main/java/org/thingsboard/server/dao/model/sql/AuditLogEntity.java
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@ -25,10 +25,7 @@ import org.thingsboard.server.common.data.EntityType;
import org.thingsboard.server.common.data.audit.ActionStatus;
import org.thingsboard.server.common.data.audit.ActionType;
import org.thingsboard.server.common.data.audit.AuditLog;
import org.thingsboard.server.common.data.id.AuditLogId;
import org.thingsboard.server.common.data.id.CustomerId;
import org.thingsboard.server.common.data.id.EntityIdFactory;
import org.thingsboard.server.common.data.id.TenantId;
import org.thingsboard.server.common.data.id.*;
import org.thingsboard.server.dao.model.BaseEntity;
import org.thingsboard.server.dao.model.BaseSqlEntity;
import org.thingsboard.server.dao.model.ModelConstants;
@ -100,6 +97,9 @@ public class AuditLogEntity extends BaseSqlEntity<AuditLog> implements BaseEntit
this.entityId = toString(auditLog.getEntityId().getId());
this.entityType = auditLog.getEntityId().getEntityType();
}
if (auditLog.getUserId() != null) {
this.userId = toString(auditLog.getUserId().getId());
}
this.entityName = auditLog.getEntityName();
this.userName = auditLog.getUserName();
this.actionType = auditLog.getActionType();
@ -121,6 +121,9 @@ public class AuditLogEntity extends BaseSqlEntity<AuditLog> implements BaseEntit
if (entityId != null) {
auditLog.setEntityId(EntityIdFactory.getByTypeAndId(entityType.name(), toUUID(entityId).toString()));
}
if (userId != null) {
auditLog.setUserId(new UserId(toUUID(entityId)));
}
auditLog.setEntityName(this.entityName);
auditLog.setUserName(this.userName);
auditLog.setActionType(this.actionType);